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Let A, B, C, D, E are the 5 jockeys riding 5 horses in a horse race. The probability distribution of their winning is tabulated as

 

Jockey Name

A

B

C

D

E

Probability

1/4

1/6

1/3

1/12

1/6

Mr.Pintraj has placed his bet on A and D. What is the probability that Pintraj may win is

in Mathematical Logic by (22 points) | 17 views
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$0.135$ ?
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Pint A or D win =P(A)+P(D)   [Mutual exclusion]

                         =1/4 + 1/12

                         =1/3


this is what the solution says in the test series and hence i am confused as to how is this valid ?

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