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Station A needs to send a message consisting of 15 packets to station B using a sliding window(window size 4) and Go-back-N error control strategy.All packets are ready and immediately available for transmission. If every 6th packet that A transmit gets lost(but no acknowledgement from B every last) Then what is the number of packet that A transmit for sending the message B?


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This is how I understand it. The miss is shown bold and underlined

1 2 3 4 5 [6 7 8 9]  6 7 [8 9 10 11] 8 9 [10 11 12 13] 10 11 [12 13 14 15] 12 13 [14 15] 14 15

Comes to 33 transmissions in all. Can you share your working on how you got 21 ?

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