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They have only asked about the memory references and alu references. In each phase we need to consider the memory reference and alu reference that was made.
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@mellophi

so you are considering cycles for the write-back phase also??
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Yeah but all write backs are in registers. So only register references are made
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@mellophi could you pls share your detailee solution
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  IF ID OF(S1) OF(S2) PD WB
I1 1MR 2MR 1MR - - 1RR
I2 1MR 3MR 2MR - - 1RR
I3 1MR 1MR 1RR 1RR 1ALU 1RR
I4 1MR 3MR 2MR - - 1RR
I5 1MR - 1RR 1RR 1ALU 1RR

From the above table if you calculate the number of cycles you will get 59. 

Time required = $ 59 \times \frac{1}{5} \times 10^{-9} sec = 11.8 ns$

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