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Bag contains 5 black, 2 red and 3 white marbles. Three marbles are drawn simultaneously. Find probability that they're of different colour
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$\frac{1}{4}$?

$$\frac{{5\choose1}\times{2\choose1}\times{3\choose1}}{{10\choose3}}$$
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having 3 different color marbles

(5/10  x 2/9 x 3/8) x 3! = 1/4 = 0.25

having 2 same colors and 1 different color marbles

1 – ((5/10 x 4/9 x 3/8) + (3/10 x 2/9 x 1/8)) = 1 – 0.275 = 0.725

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