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Consider the following (incomplete) schedule S: T1:R(X), T1:R(Y), T1:W(X), T2:R(Y), T3:W(Y), T1:W(X), T2:R(Y) If all three transactions eventually commit, show the serializability graph.
in Databases 9 points 15 views

1 Answer

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Dependency exist between T1 and T3, T2 and T3 , T3 and T2 ( Dirty Read ) .

Conclusion inferred – cycle exist in precendese graph hence not CSS
11 points
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