31 views

This is what I got:

First(S)={b}

First(A)={b}

First(B)={b,e}

First(C)={b,e,epsilon}

Follow(S)={$,d} Follow(A)={a,b,e} Follow(B)={a,b,d,e,$}

Follow(C)={a,b,e,\$}

| 31 views

Follow of B must contain a, as we can see that Follow(B) = Follow(C), which in turn results to FOLLOW(A) and FOLLOW(A) should contain a. As no other options has a in their follow set, we can go with option d.

So yes, u are right.

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Thanks Nobi. :D Upvoted and marked as best.
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cheers..  :)
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given answer is correct.. Note that follow(B) = first(C)
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@shaik

see the last production

C→ BB

here Follow(B) =Follow(C)
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ya, it's my mistake !