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Recent questions tagged closure-property
0
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0
answers
20
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GATE2017-2-04 Video Solution
Let $L_1, L_2$ be any two context-free languages and $R$ be any regular language. Then which of the following is/are CORRECT? $L_1 \cup L_2$ is context-free $\overline{L_1}$ is context-free $L_1 - R$ is context-free $L_1 \cap L_2$ is context-free I, II and IV only I and III only II and IV only I only
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
20
views
gate2017-2
theory-of-computation
closure-property
video-solution
0
votes
0
answers
22
views
GATE2013-17 Video Solution
Which of the following statements is/are FALSE? For every non-deterministic Turing machine, there exists an equivalent deterministic Turing machine. Turing recognizable languages are closed under union and complementation. Turing decidable languages are closed under intersection ... languages are closed under union and intersection. 1 and 4 only 1 and 3 only 2 only 3 only
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
22
views
gate2013
theory-of-computation
normal
closure-property
video-solution
0
votes
0
answers
23
views
GATE2016-2-18 Video Solution
Consider the following types of languages: $L_{1}$: Regular, $L_{2}$: Context-free, $L_{3}$: Recursive, $L_{4}$: Recursively enumerable. Which of the following is/are TRUE ? $\overline{L_{3}} \cup L_{4}$ is recursively enumerable. $\overline{L_{2}} \cup L_{3}$ ... $L_{1} \cup \overline{L_{2}}$ is context-free. I only. I and III only. I and IV only. I, II and III only.
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
23
views
gate2016-2
theory-of-computation
regular-languages
context-free-languages
closure-property
normal
video-solution
0
votes
1
answer
20
views
GATE2018-7 Video Solution
The set of all recursively enumerable languages is: closed under complementation closed under intersection a subset of the set of all recursive languages an uncountable set
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
20
views
gate2018
theory-of-computation
closure-property
easy
video-solution
0
votes
0
answers
16
views
GATE2006-IT-32 Video Solution
Let $L$ be a context-free language and $M$ a regular language. Then the language $L ∩ M$ is always regular never regular always a deterministic context-free language always a context-free language
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
16
views
gate2006-it
theory-of-computation
closure-property
easy
video-solution
0
votes
0
answers
18
views
GATE1989-3-ii Video Solution
Context-free languages and regular languages are both closed under the operation (s) of : Union Intersection Concatenation Complementation
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
18
views
gate1989
easy
theory-of-computation
closure-property
video-solution
0
votes
0
answers
16
views
GATE2002-2.14 Video Solution
Which of the following is true? The complement of a recursive language is recursive The complement of a recursively enumerable language is recursively enumerable The complement of a recursive language is either recursive or recursively enumerable The complement of a context-free language is context-free
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
16
views
gate2002
theory-of-computation
easy
closure-property
video-solution
0
votes
0
answers
17
views
GATE1992-16 Video Solution
Which of the following three statements are true? Prove your answer. The union of two recursive languages is recursive. The language $\{O^n \mid n\text{ is a prime} \}$ is not regular. Regular languages are closed under infinite union.
admin
asked
in
Theory of Computation
Apr 18, 2020
by
admin
589
points
17
views
gate1992
theory-of-computation
normal
closure-property
video-solution
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