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Peterson algorithm process synchronisation
How Peterson algorithm satisfies the progress requirement. As we can see when process P1 execute first and initially turn = 1 and both flags are False. After P1 execute till instruction 2 (i.e. flag[1]=true and turn = 2) preemption ... As both the condition are true then process p1 will wait for p2. Iam not understanding how progress will work here.?
asked in Operating System Aug 18, 2021
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