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Consider a file of 3MB that needs to be transmitted over a 1Gbps link with RTT of 80ms, What is the effective throughput?

A)36.2 Mbps

B)9.26Mbps

C)9.9 Mbps

D)28.85 Mbps
in Computer Networks by (5 points) | 15 views

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Transmission time= (3*$10^3$)/10^9=3msec

Propagation time =tp=rtt/2

Efficiency=Tt/Tt+rtt=0.036144578

throughput=efiiciency* bw=36144578.31=36.2Mb
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