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Consider a file of 3MB that needs to be transmitted over a 1Gbps link with RTT of 80ms, What is the effective throughput?
A)36.2 Mbps
B)9.26Mbps
C)9.9 Mbps
D)28.85 Mbps
computernetwork
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Feb 13
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Humble_student
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Transmission time= (3*$10^3$)/10^9=3msec
Propagation time =tp=rtt/2
Efficiency=Tt/Tt+rtt=0.036144578
throughput=efiiciency* bw=36144578.31=36.2Mb
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Nihar Ranjan Panda
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