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in Mathematical Logic by (37 points) | 28 views
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$1$ . we will select ‘2’ from the set.
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No given answer is 3

1 Answer

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I understood what they are trying to say.

Suppose we wrote $9$ numbers $1,2,3,4,5,6,7,8,9$ each on different piece of paper and then put all those papers in a box and we shuffle those pieces.

Now how many minimum number of pieces we need to take out from that box to ensure that the number written on any $2$ of the pieces that we are taking out from the box results in $even$ number without looking at the numbers that we are picking out.

here the name of the box is $S$. i.e. box=set.


The answer will $3$.

ROUND 1

suppose we take any number from the box then it may be $even$ or $odd$.

if $even$ say $4$ then our job is done.

if $odd$ say $9$ then we need to pick another number from the box and so we go for Round 2.

 

ROUND 2

In the pick for 2nd time

if $odd$ say $7$ comes then then our job is done. since $9+7 =16 = even$

if $even$ number comes say $4$ then we need to take out another number which can again be $even$ or $odd$. ($\because$ $4+9=13$ is odd). i.e. we need to go for Round 3.

 

ROUND 3

in the 3rd pick

if an even number say $2$ comes then $2+4=6=even$

if an odd number say $5$ comes then $5+9=14=even$

We don’t need to go for round $4$

 

i.e. we need to take out atleast $3$ numbers from the box to ensure that any of those $2$ numbers result in $even$ sum.

hence $3$ is the answer.

by (4.1k points)
edited by
0
But they should have mentioned that.

We are picking up the numbers without looking at them.right?

And the question should be somewhat like this.I think.:)

What is the minimum number to be fully confident that we get an even number.
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yes...correct. if we are able to look in the set then obviously the question would make no sense ...as we could directly pick any $2$ numbers of our own choice.
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Now a days, we have to not only answer the question but also need to make questions too :)
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