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A logic circuit has three inputs w, x, y and an output z. This output ‘z’ is ‘1’ for the following combinations.

(i) When x is True (1) and y is False (0)

(ii) When w and x are False (0)

(iii) When w, x, y are False (0)

Then the minimized expression for z is?

1.

2.

3.

4.

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0
Draw the kmap and put $1$ in these cases→
(i) When x is True (1) and y is False (0)

(ii) When w and x are False (0)

(iii) When w, x, y are False (0)

Now this will be a cake walk for u